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- Consider the iLP: min cTx s.t. Ax b where A= 1 3 1 1 0 3 0 1 2 2 3 1 1 5 1 b= 3 2 4 2 6 c= 5 5 3 Verifythatx(0)=(1131)T isaverte
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- Consider the differential equation d x d t = ( 1 − x ) ( x − 4 ) ( x − 8 )^2 The smallest critical value is x = . The solution c
